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v3.2.0 - Deploy lambda_control parameter in robyn_run()
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@gufengzhou gufengzhou released this 27 Oct 07:51
· 1395 commits to main since this release
v3.2.0
ef1b7aa
  • The lambda_control parameter in robyn_run() takes on numeric value from 0-1 and tunes L2 regularization between lambda.min and lambda.1se. Default sets lambda_control = 1, meaning lambda.1se. Reducing lambda_control results in reduction of regularization.
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