TwoCrystalBalls Solution Edge Case

[a89529294]

If true happens right at one of the jump points the current solution will return -1

test("two crystal balls", function () {
    const data = [
        false,
        false,
        false,
        true,
        true,
        true,
        true,
        true,
        true,
        true,
    ];
    const idx = 3;
    expect(two_crystal_balls(data)).toEqual(idx);
    expect(two_crystal_balls(new Array(821).fill(false))).toEqual(-1);
});

We just need to modify the second loop in TwoCrystalBalls.ts like this

for (let j = 0; j < jmpAmount + 1 && i < breaks.length; i++, j++) {
        if (breaks[i]) return i;
    }

[echosonusharma]

or you could just j <= jupAmount. i guess you are right!

[MikesGlitch]

I've been pulling my hair out on this one 😆 Yeah I ended up with the same j <= jumpIncrement