8000p-1

#8000之當月LIVE P要求 (待改成等差數列版

import math  #無條件進位

date = input()
#首項 = 0
date = int(date) #公差

'''
d = 0
d = int(d)

end = 0
#sum = (a+end) * n / 2

while (((0+end) * date / 2) >= 8000):
  end += d
  date += 1
end -= d
date -= 1

sum = int((0+end) * date / 2)
print(sum, date, d)'''

d = 0
d = 8000 / date
d1 = math.ceil(d)
sum = 0
sum = d1 * date




print(f'這個月總共有{date:d}天，所以每日要打{d1:d}LIVE P，總共會有{sum:d}個 LIVE P')